7m^2+49m=-70

Solution for 7m^2+49m=-70 equation:

7m^2+49m=-70

We move all terms to the left:

7m^2+49m-(-70)=0

We add all the numbers together, and all the variables

7m^2+49m+70=0

a = 7; b = 49; c = +70;
Δ = b2-4ac
Δ = 492-4·7·70
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-21}{2*7}=\frac{-70}{14}
=-5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+21}{2*7}=\frac{-28}{14}
=-2
$